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(2x-3)^2-(2x+1)(2x+5)=3x-14
We move all terms to the left:
(2x-3)^2-(2x+1)(2x+5)-(3x-14)=0
We get rid of parentheses
(2x-3)^2-(2x+1)(2x+5)-3x+14=0
We multiply parentheses ..
-(+4x^2+10x+2x+5)+(2x-3)^2-3x+14=0
We add all the numbers together, and all the variables
-(+4x^2+10x+2x+5)-3x+(2x-3)^2+14=0
We get rid of parentheses
-4x^2-10x-2x-3x+(2x-3)^2-5+14=0
We add all the numbers together, and all the variables
-4x^2-15x+(2x-3)^2+9=0
We move all terms containing x to the left, all other terms to the right
-4x^2-15x+(2x-3)^2=-9
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